Fie f:(1,∞)→Rf:(1,\infty)\to\mathbb{R}f:(1,∞)→R, f(y)=∫0y1x2−2x+y dxf(y)=\displaystyle\int_0^y \dfrac{1}{x^2-2x+y}\,dxf(y)=∫0yx2−2x+y1dx. Calculați ∫210f(y) dy\displaystyle\int_2^{10} f(y)\,dy∫210f(y)dy.
a) 3π3\pi3π; b) 2π2\pi2π; c) 5π3\dfrac{5\pi}{3}35π; d) π\piπ; e) π2\dfrac{\pi}{2}2π; f) 3π2\dfrac{3\pi}{2}23π.