Să se calculeze I=∫−221(x2+4)(3x+1) dxI=\int_{-2}^{2}\dfrac{1}{(x^2+4)(3^x+1)}\,dxI=∫−22(x2+4)(3x+1)1dx.
a) I=π3I=\dfrac{\pi}{3}I=3π; b) I=0I=0I=0; c) I=π20I=\dfrac{\pi}{20}I=20π; d) I=π4I=\dfrac{\pi}{4}I=4π; e) I=π10I=\dfrac{\pi}{10}I=10π; f) I=π8I=\dfrac{\pi}{8}I=8π.