Fie f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R o funcție derivabilă, astfel încât x2+2∫0xt⋅f(t) dt+2=(x2+1)⋅f(x)+ln2x^2+2\int_0^x t\cdot f(t)\,dt+2=(x^2+1)\cdot f(x)+\ln 2x2+2∫0xt⋅f(t)dt+2=(x2+1)⋅f(x)+ln2, (∀) x∈R(\forall)\, x\in\mathbb{R}(∀)x∈R. Atunci ∫01f(x) dx\int_0^1 f(x)\,dx∫01f(x)dx este:
a) π2\dfrac{\pi}{2}2π; b) π\piπ; c) 111; d) π3\dfrac{\pi}{3}3π; e) π4\dfrac{\pi}{4}4π; f) 3π4\dfrac{3\pi}{4}43π.